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Maximizing Area: Calculus Edition

Written by Ashish Bansal | Oct 23, 2024 12:57:21 AM

Hey everyone! Today, we're diving into a classic geometry problem with a calculus twist. Get ready to unlock the secrets of maximizing area!

The Challenge:

Imagine you have a rectangle with a perimeter of 32 units. What dimensions will give you the biggest possible area?

Let's Break it Down:

Step 1: Setting the Stage

We know that the perimeter of a rectangle is twice the sum of its length (l) and width (w): P = 2l + 2w

Since our perimeter is 32, we have: 32 = 2l + 2w

Now, let's get crafty and express the width (w) in terms of the length (l) and perimeter (P):

w = P/2 - l

Step 2: Area Time!

The area of a rectangle is simply length times width: A = l * w

Substituting our expression for 'w' from Step 1, we get:

A = l * (P/2 - l)

Step 3: Calculus to the Rescue

To find the maximum area, we need to find the critical points of the area function. This is where calculus comes in handy! Let's take the first derivative of the area function with respect to length (l):

dA/dl = P/2 - 2l

To find the critical points, we set the derivative equal to zero and solve for 'l':

P/2 - 2l = 0 2l = P/2 l = P/4

Step 4: The Grand Reveal

Substituting the value of P (32) back into the equation, we find:

l = 32/4 = 8

So, the length that maximizes the area is 8 units. Plugging this back into our perimeter equation, we find the width is also 8 units.

The Answer:

To get the maximum area out of a rectangle with a perimeter of 32 units, you need to make it a square with sides of 8 units each. This gives you a maximum area of 64 square units.

But wait, there's more!

We've solved it for a perimeter of 32, but what about any perimeter? Looking back at Step 3, we found that l = P/4This means that for any given perimeter, the maximum area of a rectangle is achieved when it's a square with sides of length P/4.

Cool, right?

Calculus allows us to generalize this solution and find the maximum area for any rectangle, no matter the perimeter.

Challenge Yourself:

Can you use this newfound knowledge to find the maximum area of a rectangle with a perimeter of 50 units? Let us know in the comments!